How to Accurately Retrieve the \'display\' Property of DOM Elements?
Oct 20, 2024 am 07:14 AM
Retrieving the Display Property of a DOM Element
You've encountered a discrepancy in retrieving the 'display' property of HTML elements. While you might expect to obtain 'none' or 'block' initially, this is not the case. Let's investigate the underlying reason.
In your example code, you're accessing the 'style' property of the elements' styles. However, these properties correspond to the inline styles defined in the 'style' attribute, not the computed styles applied to the elements. To access the actual applied styles, you should instead use the 'getComputedStyle' method.
<code class="javascript">var a = document.getElementById('a');
var p = document.getElementById('p');
const aStyle = getComputedStyle(a);
const pStyle = getComputedStyle(p);
alert(aStyle.display);
alert(pStyle.display);</code>
This snippet will accurately display the actual computed 'display' properties of the elements, which should be 'none' for the 'a' element and 'block' for the 'p' element.
It's important to distinguish between styles defined in the 'style' attribute and those applied by the browser. The former takes precedence over the latter, but 'getComputedStyle' returns the values of the properties that are actually applied to the DOM elements.
As an alternative, consider using CSS classes to manage the display property of elements. This approach separates presentation from logic, providing greater control and flexibility.
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