


How to Retrieve Argument Types of Function Pointers in Variadic Template Classes?
Oct 31, 2024 am 02:49 AMRetrieving Argument Types of Function Pointers in Variadic Template Classes
Generic functors are useful classes that provide a convenient way to handle functions with varying argument lists. However, accessing the argument types of function pointers within these classes can be a challenge.
Solution
Consider the following functor class:
<code class="cpp">template <typename... ARGS> class Foo { std::function<void(ARGS...)> m_f; public: Foo(std::function<void(ARGS...)> f) : m_f(f) {} void operator()(ARGS... args) const { m_f(args...); } };</code>
While you can easily access the args... in the operator() method using a recursive "peeling" function, obtaining the argument types in the constructor is more complex.
To address this, you can implement a function_traits class:
<code class="cpp">template<typename T> struct function_traits; template<typename R, typename ...Args> struct function_traits<std::function<R(Args...)>> { static const size_t nargs = sizeof...(Args); typedef R result_type; template<size_t i> struct arg { typedef typename std::tuple_element<i, std::tuple<Args...>>::type type; }; };</code>
With this class, you can determine the argument types, return type, and number of arguments of a function pointer.
Test Code
The following code demonstrates the functionality:
<code class="cpp">struct R {}; struct A {}; struct B {}; void main() { typedef std::function<R(A, B)> fun; cout << std::is_same<R, function_traits<fun>::result_type>::value << endl; cout << std::is_same<A, function_traits<fun>::arg<0>::type>::value << endl; cout << std::is_same<B, function_traits<fun>::arg<1>::type>::value << endl; }</code>
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