


Go language single linked list deletion node: Why can't you change the linked list structure directly by modifying the pointer?
Apr 02, 2025 pm 02:30 PMGo language single linked list deletion node: detailed explanation of pointer transfer and value modification
This article discusses the problem of pointer passing in Go single linked list deletion node operation, explains why directly modifying pointers cannot change the linked list structure, and provides the correct solution.
Problem: Direct modification of pointer is invalid
Go language function parameters adopt a value transfer mechanism. Even if the parameter is a pointer type, it is passed a copy of the pointer value, not the pointer itself. The following code snippet demonstrates this problem:
type linklist struct { next *linklist data interface{} } func newnodelist(value interface{}) *linklist { return &linklist{data: value, next: nil} } func (l *linklist) delete(index int) { if index == 0 { l = l.next // Modify only local replicas} } func main() { list := newnodelist(1) list.delete(0) // list not modified}
The delete
function tries to delete the first node of the linked list. However, l = l.next
only modified the value of the local variable l
inside the function, and the original linked list structure did not change. list
variable in main
function still points to the original head node.
Solution: Return the modified pointer
In order to correctly modify the linked list structure, the delete
function needs to return the modified linked list header pointer:
func (l *linklist) delete(index int) *linklist { if index == 0 { l = l.next } Return l }
main
function needs to reassign list
variable:
func main() { list := newnodelist(1) list = list.delete(0) // Key: reassign }
Only by returning and reassigning the value can list
variable point to the updated header.
Summarize
Understanding the Go language pointer delivery mechanism and localization of function parameters is crucial to correctly writing linked list operations. Directly modifying the received copy of pointer in the function cannot change the value of the external variable. The linked list structure must be updated by returning the modified pointer and reassigning the value.
The above is the detailed content of Go language single linked list deletion node: Why can't you change the linked list structure directly by modifying the pointer?. For more information, please follow other related articles on the PHP Chinese website!

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