There are two main ways to convert strings to integers in Java: use Integer.parseInt() or Integer.valueOf(). 1. Integer.parseInt() directly returns the int type, which is suitable for simple conversion, but cannot handle non-pure numeric strings or strings with decimal points, and the spaces before and after will be automatically ignored; 2. Integer.valueOf() returns an Integer object, suitable for scenarios where a wrapper class is required. It calls parseInt() internally, and the behavior is consistent. NumberFormatException will be thrown when the conversion fails, so it is recommended to use it with try-catch and verify the string format before conversion, such as removing commas or other non-numeric characters, or handling floating point numbers and positive and negative signs. In addition, for strings containing special formats such as millites, data must be cleaned first and then converted. Doing a good job of exception handling and input verification is the key to ensuring the stability of the program.
In Java, converting a string into an integer is a very common operation, such as when processing user input, parsing configuration files, or network data. The key is to make sure that the contents of the string are in a legal numeric format, otherwise an exception will be thrown.

Below are several methods and precautions you may use in actual development.
Use Integer.parseInt()
This is the most common and direct way:

String str = "123"; int num = Integer.parseInt(str);
Note:
- If the string is not a pure number, such as
"123abc"
or"abc"
,NumberFormatException
will be thrown. - If a string with a decimal point cannot be processed, such as
"123.45"
, an error will also be reported. - If there are spaces before and after the string, it will be automatically ignored, such as
" 123 "
can still be converted to123
normally.
Therefore, it is best to confirm whether the string complies with the specification before using it, or add try-catch to handle exceptions.

Use Integer.valueOf()
This method looks similar to the above, but returns an Integer
object:
String str = "456"; Integer numObj = Integer.valueOf(str); int num = numObj; // Automatic unboxing
Features:
- In fact,
parseInt()
is called internally, so it is essentially the same. - The returned object is suitable for where the package class is needed.
-
NumberFormatException
will also be thrown.
If you only need the basic type int
, then using parseInt()
is more direct; if you need to use a collection class (such as List<Integer>
), then you have to use valueOf()
.
Handle exceptions
The most common problem when the conversion fails is NumberFormatException
. To avoid program crashes, it is usually done to add exception handling:
String str = "not a number"; int num; try { num = Integer.parseInt(str); } catch (NumberFormatException e) { System.out.println("Invalid number format"); num = 0; // Give a default value or do other processing}
suggestion:
- When reading user input or external data sources, be sure to do exception capture.
- You can first determine whether the string is empty or contains only whitespace characters.
- If you allow floating point numbers to be rounded, you can consider first using
Double.parseDouble()
to convert, and then force it to int.
Other situations and alternatives
Sometimes you may encounter some special situations:
- The string contains non-numeric characters, such as
"12,345"
or"12 345"
. It cannot be directly transferred at this time, so it must be cleaned first. - Strings with positive and negative signs such as
" 123"
or"-456"
can be correctly identified. - If you want to write a simple conversion function yourself, you can also judge by character, but there is no need to repeat the wheel.
Simple cleaning example (remove commas):
String str = "12,345"; str = str.replace(",", ""); int num = Integer.parseInt(str); // Output 12345
Basically that's it. The conversion itself is not complicated, but it is easy to make errors due to data format problems, so it is more important to handle checksum exceptions well.
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