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Home Backend Development PHP Tutorial php 解析HTML post過來的json字符串,該怎么解決

php 解析HTML post過來的json字符串,該怎么解決

Jun 13, 2016 pm 12:01 PM
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php 解析HTML post過來的json字符串

本帖最后由 asia_deng 于 2014-07-07 15:48:48 編輯 我在js里把一個json對象轉(zhuǎn)為json字符串,然后放到一個隱含的input里提交到php
這是HTML的部分
<br /><br /><input type="hidden" name="epqsql" id="epqsql" value="[{"table":"epq","field":"stand4","max":60,"min":null}]"><br />

php里獲取到的字符串是:

[{\\"table\\":\\"a\\",\\"field\\":\\"value\\",\\"max\\":60,\\"min\\":null}]<br />

對字符串處理
<br />$json_string=$_POST['json'];<br />$json=htmlspecialchars_decode($json_string);<br />print_r(json_decode($json));//結(jié)果是空的<br />


換一下
<br />$json=stripslashes(htmlspecialchars_decode($json_string));<br />print_r(json_decode($json));//結(jié)果還是空的<br />


再改一下
<br />$json=stripslashes(stripslashes(htmlspecialchars_decode($json_string)));<br />print_r(json_decode($json));//好吧,結(jié)果還是空的<br />




------解決方案--------------------
本帖最后由 xuzuning 于 2014-07-07 15:57:51 編輯

也真難為你了,做那么復雜的編碼處理
$s = '[{\\"table\\":\\"a\\",\\"field\\":\\"value\\",\\"max\\":60,\\"min\\":null}]';<br /><br />$s = html_entity_decode($s);<br />$s = stripslashes($s);<br /><br />print_r(json_decode($s, 1));<br />
Array<br />(<br />    [0] => Array<br />        (<br />            [table] => a<br />            [field] => value<br />            [max] => 60<br />            [min] => <br />        )<br /><br />)<br /><br />

------解決方案--------------------
$str='[{\\"table\\":\\"a\\",\\"field\\":\\"value\\",\\"max\\":60,\\"min\\":null}]';<br />$new=htmlspecialchars_decode($str);<br /><br />$new=str_replace('\\','',$new);<br /><br />$new1=json_decode($new,true);<br />echo "<pre class="brush:php;toolbar:false">";<br />print_r($new1);<br />echo "
";
Array
(
????[0]?=>?Array
????????(
????????????[table]?=>?a
????????????[field]?=>?value
????????????[max]?=>?60
????????????[min]?=>?
????????)

)
------解決方案--------------------
echo?base64_encode($_POST['json']);
貼出結(jié)果
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