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How Does `std::function` Achieve Versatile Callability with Consistent Size?
How Does `std::function` Achieve Versatile Callability with Consistent Size?
Dec 02, 2024 am 11:49 AM
Implementing std::function for Versatile Callability
The std::function provides a way to encapsulate and store any type of callable while maintaining a fixed size. Despite the varying sizes of its contents, such as lambda expressions, std::function achieves this consistency through a technique known as type-erasure.
Type-Erasure for Diverse Callables
Type-erasure involves creating a common interface represented by a base class. In the case of std::function, a callable_base class defines a virtual function operator() that is implemented by derived classes for specific callable types. This approach enables std::function to store a pointer to the base class, allowing it to wrap any callable.
As each callable may have different implementations, the derived classes are created dynamically with std::function managing the allocation within the heap.
Copy Behavior and Internal State
When copying a std::function, the internal callable entity is copied, rather than shared. This behavior is evident in the following test:
int main() {
int value = 5;
typedef std::function<void()> fun;
fun f1 = [=]() mutable { std::cout << value++ << '\n'; };
fun f2 = f1;
f1(); // prints 5
fun f3 = f1;
f2(); // prints 5
f3(); // prints 6 (copy after first increment)
}
The increment after the first call to f1 does not affect f2, which indicates that f2 has its own copy of the callable entity.
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