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? ??? ??? MySQL ???? ?? ??? ??? SQL ??? ? ??

?? ??? ??? SQL ??? ? ??

Jan 01, 2025 am 02:41 AM

SQL Filtering and Sorting with Real-life Examples

? ?????? WHERE, HAVING, ORDER BY, GROUP BY ?? SQL ?? ?? ?? ?? ?? ? ?? ???? ?? ??? ?? ?????.

??

  1. ??? ??
  2. WHERE ?
  3. GROUP BY ?
  4. HAVING ?
  5. ORDER BY ??
  6. LIMIT ??
  7. DISTINCT ??
  8. AND, OR, NOT ???

??? ??

?? ???

emp_id name age department_id hire_date salary
1 John Smith 35 101 2020-01-01 5000
2 Jane Doe 28 102 2019-03-15 6000
3 Alice Johnson 40 103 2018-06-20 7000
4 Bob Brown 55 NULL 2015-11-10 8000
5 Charlie Black 30 102 2021-02-01 5500

?? ???

dept_id dept_name
101 HR
102 IT
103 Finance
104 Marketing

WHERE ?

WHERE ?? ??? ??? ?? ???? ????? ? ?????.

SQL ??

SELECT name, age, salary
FROM employees
WHERE age > 30;

??

name age salary
John Smith 35 5000
Alice Johnson 40 7000
Bob Brown 55 8000

??: WHERE ?? 30? ??? ??? ????? ?? ??????.

AND ???? ?

SELECT name, age, salary
FROM employees
WHERE age > 30 AND salary > 5000;

??

name age salary
Alice Johnson 40 7000
Bob Brown 55 8000

??: WHERE ?? 30? ??, ??? 5000 ??? ??? ??????.


GROUP BY ?

GROUP BY ?? ? ??? ?? ?? ?? ?? ?? ??? ?? ?? ?? ?? ??? ????? ? ?????.

SQL ??

SELECT name, age, salary
FROM employees
WHERE age > 30;

??

department_id employee_count
101 1
102 2
103 1

??: GROUP BY ?? ??? Department_id?? ????? ? ??? ?? ?? ?????.


HAVING ?

HAVING ?? GROUP BY ?? ??? ??? ????? ? ?????. WHERE ?? ???? ????? ?? ?? ?????.

SQL ??

SELECT name, age, salary
FROM employees
WHERE age > 30 AND salary > 5000;

??

department_id avg_salary
102 5750
103 7000

??: HAVING ?? ? ?? ??? ?? ??? ???? ??? ??????. ????? 5500 ??? ??? ?????.


ORDER BY ??

ORDER BY ?? ?? ??? ?? ???? ?? ??? ???? ? ?????. ????? ?????? ?????. ?????? ????? DESC? ?????.

SQL ??(????)

SELECT department_id, COUNT(*) AS employee_count
FROM employees
GROUP BY department_id;

??

name salary
John Smith 5000
Charlie Black 5500
Jane Doe 6000
Alice Johnson 7000
Bob Brown 8000

??: ?? ?? ?????? ??? ?????.

SQL ??(????)

SELECT department_id, AVG(salary) AS avg_salary
FROM employees
GROUP BY department_id
HAVING AVG(salary) > 5500;

??

name salary
Bob Brown 8000
Alice Johnson 7000
Jane Doe 6000
Charlie Black 5500
John Smith 5000

??: ?? ?????? ??? ?????.


LIMIT ??

LIMIT ?? ?? ???? ??? ??? ?? ???? ? ?????. ?? ??? ?? ??? ?????? ???? ? ?? ?????.

SQL ??

SELECT name, age, salary
FROM employees
WHERE age > 30;

??

name salary
Bob Brown 8000
Alice Johnson 7000
Jane Doe 6000

??: LIMIT ?? ??? ?? ?? ?? ?? 3???? ??? ?????.


DISTINCT ??

DISTINCT ?? ?? ???? ???(??) ?? ???? ??? ???? ? ?????.

SQL ??

SELECT name, age, salary
FROM employees
WHERE age > 30 AND salary > 5000;

??

department_id
101
102
103

??: DISTINCT ?? ??? ???? ??? Department_id ?? ?????.


AND, OR, NOT ???

AND, OR ? NOT ???? WHERE ??? ?? ??? ???? ? ?????.

AND ???

AND ???? ? ? ??? ??? ???? ? ?????. ???? ?? ??? true? ?? ?????.

SELECT department_id, COUNT(*) AS employee_count
FROM employees
GROUP BY department_id;

??

name age salary
Alice Johnson 40 7000
Bob Brown 55 8000

??: WHERE ?? ? ??(?? > 30 ? ?? > 5500)? ?? ?? ?? ??????.

OR ???

OR ???? ?? ? ??? ???? ?? ??? ?????.

SELECT department_id, AVG(salary) AS avg_salary
FROM employees
GROUP BY department_id
HAVING AVG(salary) > 5500;

??

name age salary
Jane Doe 28 6000
Alice Johnson 40 7000
Bob Brown 55 8000

??: WHERE ?? age < 30 ?? ?? > 7000? ????.

NOT ???

NOT ???? ??? true? ?? ???? ? ?????.

SELECT name, age, salary
FROM employees
WHERE age > 30;




??

name age salary
John Smith 35 5000
Charlie Black 30 5500
Jane Doe 28 6000

??: WHERE ?? ?? > 6000? ?????. ?, ??? 6000 ??? ??? ????? ?????.


??

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