How Can I Serialize and Deserialize Fields Using System.Text.Json?
Jan 14, 2025 am 07:22 AM
System.Text.Json: Serialization and Deserialization Fields
In newer .NET versions, System.Text.Json.JsonSerializer is the preferred JSON serialization and deserialization method. However, it poses a challenge for classes containing field variables, as these are not supported by default.
The problem
In older versions of .NET, field variables could be included in the serialization/deserialization process. With the introduction of JsonSerializer, only attributes are supported, leading to the following issues:
using System.Text.Json;
public class Car
{
public int Year { get; set; } // 正確序列化
public string Model; // 未正確序列化（字段變量）
}
static void Problem()
{
Car car = new Car()
{
Model = "Fit",
Year = 2008,
};
string json = JsonSerializer.Serialize(car); // {"Year":2008}
Car carDeserialized = JsonSerializer.Deserialize<Car>(json);
Console.WriteLine(carDeserialized.Model); // null!
}
Solution
To solve this problem, two strategies exist:
1. .NET 5 and above
Starting in .NET 5, public fields can be serialized and deserialized via:
- Set
JsonSerializerOptions.IncludeFieldstotrue - Add
[JsonInclude]attributes to fields
Example:
using System.Text.Json;
using System.Text.Json.Serialization;
static void Main()
{
var car = new Car { Model = "Fit", Year = 2008 };
// 啟用支持
var options = new JsonSerializerOptions { IncludeFields = true };
// 傳遞“options”
var json = JsonSerializer.Serialize(car, options);
// 傳遞“options”
var carDeserialized = JsonSerializer.Deserialize<Car>(json, options);
Console.WriteLine(carDeserialized.Model); // 輸出 "Fit"
}
public class Car
{
public int Year { get; set; }
[JsonInclude]
public string Model;
}
2. .NET Core 3.x
In .NET Core 3.x, field serialization is not supported. As a workaround, consider using a custom converter to achieve the desired behavior.
For more information and detailed documentation, please refer to the following resources:
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