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        function strToLeft($num,$arr){
            $i = $arr[$num];
            unset($arr[$num]);
            array_push($arr,$i);
            return $arr;
        }

        function combine_increase($arr, $start, $result, $count, $NUM, $arr_len,$newarr=array())  
        {  
          $i = 0;
          for ($i = $start; $i < $arr_len + 1 - $count; $i++)  
          {  
            $result[$count - 1] = $i;  
            if ($count - 1 == 0)  
            {  
              $tmp=array();
              for ($j = $NUM - 1; $j >= 0; $j--)  {
                array_push($tmp, $arr[$result[$j]]);
              }

              array_push($newarr, strToLeft(rand(0,$NUM-1),$tmp));
            }  
            else  {
              return combine_increase($arr, $i + 1, $result, $count - 1, $NUM, $arr_len); }
            
          }  
          return $newarr;
        } 
           $arr = array('a1','b2','c3','d4','e5','x1','y1','z1');
           $num = 3;  
           $result[$num]=array();
           $newarr=array();
           echo "('a1','b2','c3','d4','e5','x1','y1','z1')";//,'e5','x1'
           echo "<br/>";
           //combine_increase($arr, 0, $result, $num, $num, count($arr));
           echo "<pre>";
           var_dump(combine_increase($arr, 0, $result, $num, $num, count($arr)));
           echo "</pre>";
           echo "<br/>";

這是一個把一維數(shù)據(jù)生成按三個元素不同組合的n個一維數(shù)組，正常如果不是返回只是把array_push($newarr, strToLeft(rand(0,$NUM-1),$tmp));句變成

          var_dump(strToLeft(rand(0,$NUM-1),$tmp));
          echo("<br/>");  
          
          則能列出幾十條結(jié)果，但通過返回數(shù)組就只返回6個，好像是前6個，不知道如何能全部返回取到，求解?。。。?/code>