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Static Initialization Blocks: Why a Separate Block?
Home Java javaTutorial Why Use Static Initialization Blocks in Java?

Why Use Static Initialization Blocks in Java?

Dec 20, 2024 pm 05:46 PM

Why Use Static Initialization Blocks in Java?

Static Initialization Blocks: Why a Separate Block?

You might have encountered the concept of "static initialization blocks" in Java. They are meant to address scenarios where assigning values to static fields cannot be done in a single line. However, you may wonder why a special block is needed for this purpose.

In Java, non-static blocks get executed every time a new instance of the class is created. Static blocks, on the other hand, are executed only once when the class itself is initialized. This holds true regardless of how many objects of that particular class you create.

Consider the following example:

public class Test {

    static {
        System.out.println("Static");
    }

    {
        System.out.println("Non-static block");
    }

    public static void main(String[] args) {
        Test t = new Test();
        Test t2 = new Test();
    }
}

Output:

Static
Non-static block
Non-static block

In this example, the static block containing "Static" is executed only once when the Test class is initially loaded. The non-static block containing "Non-static block" is executed every time a new instance (t and t2) of the Test class is created.

Therefore, using a static initialization block allows you to perform specific actions or assign values to static fields only once during class initialization, while non-static blocks are used for tasks that need to be performed every time an object of the class is instantiated.

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