To implement date plus several working days in PHP and skip holidays, you can use the DateTime class to combine the holiday list to make judgments. The specific steps are as follows: 1. Create a DateTime object and increase the number of days in a loop; 2. Determine whether it is Monday to Friday; 3. Check whether the current date is in the holiday list; 4. Reduce the number of days to be added only if it is a working day and not a holiday; 5. Pay attention to time zone settings, dynamic update of holiday data and performance optimization issues.
Sometimes we need to add several working days on a date basis and skip weekends and holidays. It is actually not difficult to implement this function in PHP, but you must handle details, such as the definition of holidays, time zone issues, etc.

Basic operations using DateTime class
PHP's DateTime
class provides powerful date processing capabilities. We can cycle to increase the number of days based on it and determine whether it is a working day.

function addBusinessDays($date, $days) { $date = new DateTime($date); while ($days > 0) { $date->modify(' 1 day'); $weekday = $date->format('N'); // 1 (Monday) to 7 (Sunday) if ($weekday <= 5) { // If it is Monday to Friday$days--; } } return $date->format('Ym-d'); } echo addBusinessDays('2025-04-05', 10); // The output result depends on the start date
This code will be added day by day, and if it happens to be non-weekly, it will be subtracted by a "number of days to be added". Although it is not the most efficient, it is clear in logic and is suitable for most business scenarios.
Plus holiday skip mechanism
The above method only considers weekends, and if you need to avoid statutory holidays or company custom holidays, you need to maintain an additional holiday list.

You can save holidays into an array in the format Ymd
:
$holidays = [ '2025-04-04', // Qingming Festival'2025-05-01', // Labor Day];
Then modify the function and add an extra check when determining whether it is a working day:
function addBusinessDays($date, $days, $holidays = []) { $date = new DateTime($date); $holidays = array_flip($holidays); // Convert to the form of key => date to facilitate querying while ($days > 0) { $date->modify(' 1 day'); $currentDateStr = $date->format('Ym-d'); $weekday = $date->format('N'); if ($weekday <= 5 && !isset($holidays[$currentDateStr])) { $days--; } } return $currentDateStr; }
This allows you to flexibly skip designated holidays.
Notes and optimization suggestions
Time zone problem : Make sure that your date is consistent with the server/user's time zone, and you can specify the time zone when creating a
DateTime
object:$date = new DateTime($dateStr, new DateTimeZone('Asia/Shanghai'));
Holiday data update : Holidays vary from year to year and are best fetched from a database or external API rather than hardcoded.
Performance issues : If you need to add a large number of days (such as a few working days), you can consider batch calculations and cache intermediate results to avoid traversals every day by day.
Basically that's it
The core of realizing the "adding working days to date" is to control the daily judgment conditions: whether it is a working day or whether it is a holiday. As long as the logic is clear, it is not complicated to implement with PHP. However, it is easy to ignore the management methods of holidays in actual use, which is worth paying attention to.
The above is the detailed content of php add business days to date. For more information, please follow other related articles on the PHP Chinese website!

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