table=$table; } } class b { $b = new a('abc');/" />

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Home Backend Development PHP Tutorial 可否在不繼承一個(gè)類的時(shí)候執(zhí)行一些方法

可否在不繼承一個(gè)類的時(shí)候執(zhí)行一些方法

Jun 13, 2016 pm 01:13 PM
class new php quot table

能否在不繼承一個(gè)類的時(shí)候執(zhí)行一些方法?

PHP code
<!--

Code highlighting produced by Actipro CodeHighlighter (freeware)
http://www.CodeHighlighter.com/

-->
class a
{
   public $table = '';

   public function __contruct($table)
   {
       $this->table=$table;
   }
}

class b
{
    $b = new a('abc');//Fatal error: Class 'a' not found
}



能否使用別的什么方法代替?我現(xiàn)在想在b類里完成對(duì)a類構(gòu)造函數(shù)的初始化

------解決方案--------------------
require_once ‘class_a_file.php’;
------解決方案--------------------
上面說的對(duì),出錯(cuò)并不是不能new,而是class a的代碼沒加進(jìn)來

我經(jīng)常在一個(gè)類里面new另一個(gè)
------解決方案--------------------
探討

靠,搜跌撕裂啊、我一直以為這個(gè)加載是應(yīng)該讓PHP從內(nèi)部就給我完成的,沒想到

------解決方案--------------------
取個(gè)例子,更好說明一些.
假設(shè) class a 的代碼存在 class_a.php class b 的代碼存在class_b.php 上.
PHP code

<?php function __autoload($class_name) {
      require("class_".$class_name.".php");
}

$b = new b(); //這樣會(huì)自動(dòng)去 加載 class_b.php 文件
$a = new a(); //這樣會(huì)自動(dòng)去 加載  class_a.php 文件

?> <div class="clear">
                 
              
              
        
            </div>
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