php中長文章分頁顯示實現代碼
Jun 13, 2016 am 11:57 AM
歡迎交流!實現代碼如下:
復制代碼 代碼如下:
/**
*Author:烏鳥heart
*實現長文章分頁的代碼
*原理:
*利用一個數組來記錄文章每一頁(用p0、p1、p2...做手動標記)的起始字節(jié)數,然后通過利用php函數操作這個數組去顯示分頁后的文章。分頁顯示,傳遞ptag(與tag的值一樣)值。
*利用到的php函數:
*1、strlen("字符串") - Returns the length of the given string. - 返回字符串的字節(jié)總數。
*2、strpos("字符串","匹配字符") - Returns the numeric position of the first occurrence of needle in the haystack string. - 返回字符串中出現的第一個相匹配的字符所在的字節(jié)序數。
*3、substr("字符串","起始位置","終止位置") - substr() returns the portion of string specified by the start and length parameters. - 返回字符串中指定起止位置的若干字符。
*/
$sql = "select * from article where id = 41";//定義sql語句,返回id為41的內容
$result = mysql_query($sql);//執(zhí)行sql語句,返回結果集
$row = mysql_fetch_array($result);//以數組的形式從記錄集返回
$content = $row['content'];//把文章賦給變量$content
$articleCounts = strlen($content);//返回$content(文章)的總字節(jié)數
$isTrue = true;//循環(huán)標記
$tag = 0;//分頁標記、數組下標
echo "字節(jié)總數:".$articleCounts."
";//測試信息
//尋找標記“ptag”,并把其位置(所在的字節(jié)數)賦給數組array[]------------------------------------------
while($isTrue){
$startAt = strpos($content,"p".$tag);//得到相應ptag的字節(jié)序數
if($startAt != false){ //如果有標記(返回值不是false),則記錄位置
$array[$tag++] = $startAt;
}else{ //如果沒有標記,則將數組array[0]賦值'\0'
$array[$tag] = '\0';
$isTrue = false;
}
}
//循環(huán)輸出標記位置-------------------------------------------------------------測試信息
for($i = 0; $i echo $array[$i]."
";
}
echo "------------------------------
";
//輸出內容---------------------------------------------------------------------
if($array[0] == '\0'){ //判斷是否有標記
echo $content; //沒有標記的情況,單頁顯示
}else{ //有標記的情況,分頁顯示
//輸出分頁內容
if( isset($_GET['ptag']) ){ //判斷是否有ptag值傳遞,有則顯示第 ptag+1 頁,否則顯示第一頁(ptag=0)
$ptag = $_GET['ptag']; //把ptag的值賦給變量$ptag
if($ptag echo "有值傳遞,顯示第".($ptag+1)."頁
"; //測試信息
echo "值為:".$ptag."
"; //測試信息
echo substr($content,$array[$ptag - 1] + 2,$array[$ptag] - $array[$ptag - 1] - 2);//顯示ptag+1頁的內容
}else{echo "參數有誤";}
}
else{ //沒有ptag值傳遞的情況,顯示第一頁(ptag=0)
echo "無值傳遞,顯示第1頁
"; //測試信息
echo substr($content,0,$array[0] - 1);//顯示第一頁的內容
}
}
//循環(huán)顯示頁數鏈接-------------------------------------------------------------
if($array[0] != '\0'){ //在有手動標記的情況下才顯示頁數鏈接
for($i = 0;$i if($ptag == $i){ //如果是本頁,則粗體顯示
$pager .= " ".($i+1)." ";
}else{ //不是本頁
$pager .= " ".($i+1)." ";
}
}
echo "
跳轉至第".$pager."頁"; //輸出鏈接
}
?>

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